EXY-SC-1140
第 361 题
下面 fibonacci 函数的时间复杂度为( )。
int fibonacci(int n) {
if (n <= 1)
return n;
else
return fibonacci(n - 1) + fibonacci(n - 2);
}
(注:本题GESP官方给的选项B是 $O(\phi^n), \phi = \frac{\sqrt{5}-1}{2}$)
语言:
C++
GESP真题
八级
2024.9
单选题号:
15
EXY-SC-1139
第 362 题
下面程序的 Merge_Sort 函数时间复杂度为( )。
void Merge(int a[], int left, int mid, int right) {
int temp[right - left + 1];
int i = left;
int j = mid + 1;
int k = 0;
while (i <= mid && j <= right) {
if (a[i] < a[j])
temp[k++] = a[i++];
else
temp[k++] = a[j++];
}
while (i <= mid)
temp[k++] = a[i++];
while (j <= right)
temp[k++] = a[j++];
for (int m = left, n = 0; m <= right; m++, n++)
a[m] = temp[n];
}
void Merge_Sort(int a[], int left, int right) {
if (left == right)
return;
int mid = (left + right) / 2;
Merge_Sort(a, left, mid);
Merge_Sort(a, mid + 1, right);
Merge(a, left, mid, right);
}
语言:
C++
GESP真题
八级
2024.9
单选题号:
14
EXY-SC-1138
第 363 题
下面 Floyd 算法中,横线处应该填入的是( )。
#include <iostream>
using namespace std;
#define N 21
#define INF 9999999
int map[N][N];
int main() {
int n, m, t1, t2, t3;
cin >> n >> m;
for (int i = 1; i <= n; i++) {
for (int j = 1; j <= n; j++) {
if (i == j)
map[i][j] = 0;
else
map[i][j] = INF;
}
}
for (int i = 1; i <= m; i++) {
cin >> t1 >> t2 >> t3;
map[t1][t2] = t3;
}
for (int k = 1; k <= n; k++)
for (int i = 1; i <= n; i++)
for (int j = 1; j <= n; j++)
if (________) // 在此处填入选项
map[i][j] = map[i][k] + map[k][j];
for (int i = 1; i <= n; i++) {
for (int j = 1; j <= n; j++) {
cout.width(4);
cout << map[i][j];
}
cout << endl;
}
}
语言:
C++
GESP真题
八级
2024.9
单选题号:
13
EXY-SC-1137
第 364 题
下列 Dijkstra 算法中,横线处应该填入的是( )。
#include <iostream>
using namespace std;
#define N 100
int n, e, s;
const int inf = 0x7fffffff;
int dis[N + 1];
int cheak[N + 1];
int graph[N + 1][N + 1];
int main() {
for (int i = 1; i <= N; i++)
dis[i] = inf;
cin >> n >> e;
for (int i = 1; i <= e; i++) {
int a, b, c;
cin >> a >> b >> c;
graph[a][b] = c;
}
cin >> s;
dis[s] = 0;
for (int i = 1; i <= n; i++) {
int minn = inf, minx;
for (int j = 1; j <= n; j++) {
if (________) { // 在此处填入选项
minn = dis[j];
minx = j;
}
}
cheak[minx] = 1;
for (int j = 1; j <= n; j++) {
if (graph[minx][j] > 0) {
if (minn + graph[minx][j] < dis[j]) {
dis[j] = minn + graph[minx][j];
}
}
}
}
}
语言:
C++
GESP真题
八级
2024.9
单选题号:
12
EXY-SC-1136
第 365 题
下面 Prim 算法程序中,横线处应该填入的是()。
#include <iostream>
#include <vector>
#include <algorithm>
using namespace std;
int prim(vector<vector<int>> & graph, int n) {
vector<int> key(n, INT_MAX);
vector<int> parent(n, -1);
key[0] = 0;
for (int i = 0; i < n; i++) {
int u = min_element(key.begin(), key.end()) - key.begin();
if (key[u] == INT_MAX)
break;
for (int v = 0; v < n; v++) {
if (__________) { // 在此处填入选项
key[v] = graph[u][v];
parent[v] = u;
}
}
}
int sum = 0;
for (int i = 0; i < n; i++) {
if (parent[i] != -1) {
cout << "Edge: " << parent[i] << " - " << i << " Weight: " << key[i] << endl;
sum += key[i];
}
}
return sum;
}
int main() {
int n, m;
cin >> n >> m;
vector<vector<int>> graph(n, vector<int>(n, 0));
for (int i = 0; i < m; i++) {
int u, v, w;
cin >> u >> v >> w;
graph[u][v] = w;
graph[v][u] = w;
}
int result = prim(graph, n);
cout << "Total weight of the minimum spanning tree: " << result << endl;
return 0;
}
语言:
C++
GESP真题
八级
2024.9
单选题号:
11
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